16x^2-19x+3=0

Solution for 16x^2-19x+3=0 equation:

Simplifying
16x2 + -19x + 3 = 0

Reorder the terms:
3 + -19x + 16x2 = 0

Solving
3 + -19x + 16x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(3 + -16x)(1 + -1x) = 0

Subproblem 1
Set the factor '(3 + -16x)' equal to zero and attempt to solve:

Simplifying
3 + -16x = 0

Solving
3 + -16x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -16x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -16x = 0 + -3
-16x = 0 + -3

Combine like terms: 0 + -3 = -3
-16x = -3

Divide each side by '-16'.
x = 0.1875

Simplifying
x = 0.1875
Subproblem 2
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Solution
x = {0.1875, 1}